(4x^2-20x)/(x^2-25)

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Solution for (4x^2-20x)/(x^2-25) equation: 


D( x )

x^2-25 = 0

x^2-25 = 0

x^2-25 = 0

1*x^2 = 25 // : 1

x^2 = 25

x^2 = 25 // ^ 1/2

abs(x) = 5

x = 5 or x = -5

x in (-oo:-5) U (-5:5) U (5:+oo)

(4*x^2-(20*x))/(x^2-25) = 0

(4*x^2-20*x)/(x^2-25) = 0

4*x^2-20*x = 0

4*x*(x-5) = 0

x-5 = 0 // + 5

x = 5

4*x*(x-5) = 0

(4*x*(x-5))/(x^2-25) = 0

( 4*x )

4*x = 0 // : 4

x = 0

( x-5 )

x-5 = 0 // + 5

x = 5

x in { 5} 

x = 0

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